You should have posted this before yesterday, if you wanted me to look at it and measure the angle between the moon and sun.
I can do it today because the moonrise time is only a few moments later.
But, you still have not explained what is the point of this experiment? Just get to the point. What is it you think can be shown by measuring the angle between moon's position at rise and where the sun is in relation to it at that moment?
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It's not
moon's position at rise. You keep saying that and I have no idea where you got it.
We're not concerned with moonrise, UNLESS that is the moment when the first or last quarter moon occurs that day. I have given you links to the Almanac website that displays the times for each quarter moon but maybe you think that's part of the great conspiracy or whatever. You're going to have to get OVER that prejudice if you want to observe the facts without prejudice.
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I know, I should have posted it before yesterday. But what is, what is. Now we'll have to wait for the next opportunity. A measurement can be taken on May 1st in the evening, and two more on May 2nd in the morning and in the evening. The first quarter happens at 7:48 pm which is 9 minutes after sunset (7:39 pm). So the sun will be very low in the sky, and the moon will be somewhere overhead. --- Can you predict about where in the sky the moon will be on May 2nd when the sun is setting?
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The sun, moon and planets make regular motions in the sky, which allow us to predict where they will be, even many years in advance. Can you explain how that would be possible with a "flat" earth model? Are there any astronomical charts and tables written by flat-earthers? For example, if a viewer in California measures the angle between the moon and sun as 93 degrees like I did, and another viewer in Hawaii sees the same 93 degrees and another viewer in Quito, Equador and another in Calgary, Alberta, Canada sees 93 degrees and another in Houston TX also sees 93 degrees, all of them at the same hour (5:00 PDT, or UTC -7), how would you explain that set of data using a flat-earth model? But in any case, there is a lot more to this process, but it would only bog down the topic at this point. Go watch the video if you want the whole process.
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Measurements taken today are not of
no use, but they are unable to show the key picture that we need for the next phase. We need to see what the angle is between the moon and the sun as viewed from earth at the moment of the quarter moon. And that moment has passed for this phase. The next quarter will be the LAST quarter moon, on April 19th. Remember, during the last quarter, the moon leads the sun, so the moon will be about 6 hours ahead of the sun. The last quarter occurs at 3:00 am, therefore the moon will be around the 9 o'clock position of a 24-hour clock, which is 10:30 on a 12-hour clock. Since the sun moves faster than the moon, the sun will be catching up to the moon that morning on Wednesday the 19th of April. If we get a chance to measure the angle between them as the sun rises, it is going to be a smaller angle than it was at 3:00 am, but how much smaller is another question.
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Today the area of the illuminated moon has increased 11% from yesterday, from 50% to 61%. So we can see that the angle of the sun to the moon is significantly changing. This has many implications.
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The point of the experiment is to complete the picture of the relative positions of the earth, moon and sun at the moment of the first or last quarter moon each month. This position occurs 24 times each year, so the data is very available for those who want to know
what reality has to show us. I already posted a video that goes through the whole process if you want to watch that again -- or, perhaps for the first time, if you have not yet watched the videos I've posted.
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I make it a point to watch the F-E-er's videos all right, but they don't bother to watch mine, apparently. Because if they had watched them they wouldn't be asking these questions over and over again. Maybe it's too much work to spend 20 minutes every few days or whatever.
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