That "curve" picture is obviously garbage. Tahoe is about 21 miles in length (at its longest point), which would translate to a 295 foot cuvature, so 125 foot drop on each end from center, so the NASA curve is clearly exaggerated. It would be nice to get a picture of Tahoe lengthwise to see if the 125-foot curvature is detectable. Problem with obtaining such a picture of Tahoe is that to get the entire 21 miles within the picture from a low-enough angle so you could see the water-line from end to end, you'd have to be so far away from it that various land features would get in the way, and the 125 might be harder to see. I believe the picture in this link is showing Tahoe width-wise not length-wise.
To me, what's really conclusive is that, if you look at those weather balloon photos from 120,000 feet, and see how high that elevation is, according to globe math, the curvature of Kansas from end to end would be about 110,000 feet, so up the height of the balloon. No such curvature is visible from 120,000 feet. So, Neil deGrasse Tyson actually lies when he claims that no curvature is visible from 120,000 feet. Certainly it wouldn't look like the fake RedBull video where it looks it curve down about 50 miles within 10 miles. But if you looked around in any direction from 120,000 feet, the curve should be noticeable by way of a significant drop in the level of the horizon. It should not stay up at eye level.